Distance from Centerville to Sveti Ivan Zelina
The shortest distance (air line) between Centerville and Sveti Ivan Zelina is 4,752.00 mi (7,647.61 km).
How far is Centerville from Sveti Ivan Zelina
Centerville is located in Ohio, United States within 39° 38' 2.04" N -85° 51' 18.36" W (39.6339, -84.1449) coordinates. The local time in Centerville is 18:41 (15.11.2024)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 00:41 (16.11.2024)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,752.00 miles which is equal to 7,647.61 km.
Centerville, Ohio, United States
Related Distances from Centerville
Sveti Ivan Zelina, Zagrebačka županija, Croatia