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      Distance from Ceres to Chateauneuf-les-Martigues

      The shortest distance (air line) between Ceres and Chateauneuf-les-Martigues is 5,903.18 mi (9,500.24 km).

      How far is Ceres from Chateauneuf-les-Martigues

      Ceres is located in California, United States within 37° 35' 42.72" N -121° 2' 16.8" W (37.5952, -120.9620) coordinates. The local time in Ceres is 17:30 (16.11.2024)

      Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 02:30 (17.11.2024)

      The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 5,903.18 miles which is equal to 9,500.24 km.

      Ceres, California, United States

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      Chateauneuf-les-Martigues, Bouches-du-Rhône, France

      Related Distances to Chateauneuf-les-Martigues