Distance from Cesky Tesin to Bloomington
The shortest distance (air line) between Cesky Tesin and Bloomington is 4,816.34 mi (7,751.14 km).
How far is Cesky Tesin from Bloomington
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 23:49 (04.10.2025)
Bloomington is located in Illinois, United States within 40° 28' 32.52" N -89° 1' 46.92" W (40.4757, -88.9703) coordinates. The local time in Bloomington is 16:49 (04.10.2025)
The calculated flying distance from Bloomington to Bloomington is 4,816.34 miles which is equal to 7,751.14 km.
Cesky Tesin, Moravskoslezský kraj, Czechia
Related Distances from Cesky Tesin
Bloomington, Illinois, United States