Distance from Cesky Tesin to East Patchogue
The shortest distance (air line) between Cesky Tesin and East Patchogue is 4,215.40 mi (6,784.02 km).
How far is Cesky Tesin from East Patchogue
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 19:05 (06.10.2025)
East Patchogue is located in New York, United States within 40° 46' 13.44" N -73° 1' 5.88" W (40.7704, -72.9817) coordinates. The local time in East Patchogue is 13:05 (06.10.2025)
The calculated flying distance from East Patchogue to East Patchogue is 4,215.40 miles which is equal to 6,784.02 km.
Cesky Tesin, Moravskoslezský kraj, Czechia
Related Distances from Cesky Tesin
East Patchogue, New York, United States