Distance from Cesky Tesin to Evansville
The shortest distance (air line) between Cesky Tesin and Evansville is 4,895.45 mi (7,878.47 km).
How far is Cesky Tesin from Evansville
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 21:27 (08.10.2025)
Evansville is located in Indiana, United States within 37° 59' 17.16" N -88° 27' 57.24" W (37.9881, -87.5341) coordinates. The local time in Evansville is 14:27 (08.10.2025)
The calculated flying distance from Evansville to Evansville is 4,895.45 miles which is equal to 7,878.47 km.
Cesky Tesin, Moravskoslezský kraj, Czechia
Related Distances from Cesky Tesin
Evansville, Indiana, United States