Distance from Cesky Tesin to Fountain Hills
The shortest distance (air line) between Cesky Tesin and Fountain Hills is 5,925.70 mi (9,536.49 km).
How far is Cesky Tesin from Fountain Hills
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 21:51 (06.10.2025)
Fountain Hills is located in Arizona, United States within 33° 36' 26.28" N -112° 15' 36.72" W (33.6073, -111.7398) coordinates. The local time in Fountain Hills is 13:51 (06.10.2025)
The calculated flying distance from Fountain Hills to Fountain Hills is 5,925.70 miles which is equal to 9,536.49 km.
Cesky Tesin, Moravskoslezský kraj, Czechia
Related Distances from Cesky Tesin
Fountain Hills, Arizona, United States