Distance from Cesky Tesin to Fountain Valley
The shortest distance (air line) between Cesky Tesin and Fountain Valley is 6,087.09 mi (9,796.23 km).
How far is Cesky Tesin from Fountain Valley
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 01:40 (07.10.2025)
Fountain Valley is located in California, United States within 33° 42' 37.8" N -118° 2' 54.96" W (33.7105, -117.9514) coordinates. The local time in Fountain Valley is 16:40 (06.10.2025)
The calculated flying distance from Fountain Valley to Fountain Valley is 6,087.09 miles which is equal to 9,796.23 km.
Cesky Tesin, Moravskoslezský kraj, Czechia
Related Distances from Cesky Tesin
Fountain Valley, California, United States