Distance from Cesky Tesin to Sankt Polten
The shortest distance (air line) between Cesky Tesin and Sankt Polten is 173.30 mi (278.90 km).
How far is Cesky Tesin from Sankt Polten
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 17:29 (27.11.2024)
Sankt Polten is located in Sankt Pölten, Austria within 48° 12' 0" N 15° 37' 0.12" E (48.2000, 15.6167) coordinates. The local time in Sankt Polten is 17:29 (27.11.2024)
The calculated flying distance from Sankt Polten to Sankt Polten is 173.30 miles which is equal to 278.90 km.
Cesky Tesin, Moravskoslezský kraj, Czechia
Related Distances from Cesky Tesin
Sankt Polten, Sankt Pölten, Austria