Distance from Champlin to Aleksandrovac
The shortest distance (air line) between Champlin and Aleksandrovac is 5,111.29 mi (8,225.83 km).
How far is Champlin from Aleksandrovac
Champlin is located in Minnesota, United States within 45° 10' 12.72" N -94° 36' 34.92" W (45.1702, -93.3903) coordinates. The local time in Champlin is 04:36 (13.03.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 11:36 (13.03.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,111.29 miles which is equal to 8,225.83 km.
Champlin, Minnesota, United States
Related Distances from Champlin
Aleksandrovac, Rasinska oblast, Serbia