Distance from Champlin to Aleksandrow Lodzki
The shortest distance (air line) between Champlin and Aleksandrow Lodzki is 4,635.20 mi (7,459.63 km).
How far is Champlin from Aleksandrow Lodzki
Champlin is located in Minnesota, United States within 45° 10' 12.72" N -94° 36' 34.92" W (45.1702, -93.3903) coordinates. The local time in Champlin is 14:51 (09.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 21:51 (09.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,635.20 miles which is equal to 7,459.63 km.
Champlin, Minnesota, United States
Related Distances from Champlin
Aleksandrow Lodzki, Łódzki, Poland