Distance from Champlin to Bad Sassendorf
The shortest distance (air line) between Champlin and Bad Sassendorf is 4,290.81 mi (6,905.39 km).
How far is Champlin from Bad Sassendorf
Champlin is located in Minnesota, United States within 45° 10' 12.72" N -94° 36' 34.92" W (45.1702, -93.3903) coordinates. The local time in Champlin is 22:04 (14.03.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 05:04 (15.03.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,290.81 miles which is equal to 6,905.39 km.
Champlin, Minnesota, United States
Related Distances from Champlin
Bad Sassendorf, Soest, Germany