Distance from Champlin to Begijnendijk
The shortest distance (air line) between Champlin and Begijnendijk is 4,199.17 mi (6,757.92 km).
How far is Champlin from Begijnendijk
Champlin is located in Minnesota, United States within 45° 10' 12.72" N -94° 36' 34.92" W (45.1702, -93.3903) coordinates. The local time in Champlin is 14:45 (19.01.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 21:45 (19.01.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,199.17 miles which is equal to 6,757.92 km.
Champlin, Minnesota, United States
Related Distances from Champlin
Begijnendijk, Arr. Leuven, Belgium