Distance from Champlin to Celakovice
The shortest distance (air line) between Champlin and Celakovice is 4,572.28 mi (7,358.37 km).
How far is Champlin from Celakovice
Champlin is located in Minnesota, United States within 45° 10' 12.72" N -94° 36' 34.92" W (45.1702, -93.3903) coordinates. The local time in Champlin is 13:41 (01.02.2025)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 20:41 (01.02.2025)
The calculated flying distance from Celakovice to Celakovice is 4,572.28 miles which is equal to 7,358.37 km.
Champlin, Minnesota, United States
Related Distances from Champlin
Celakovice, Středočeský kraj, Czechia