Distance from Champlin to Sannicolau Mare
The shortest distance (air line) between Champlin and Sannicolau Mare is 4,963.47 mi (7,987.93 km).
How far is Champlin from Sannicolau Mare
Champlin is located in Minnesota, United States within 45° 10' 12.72" N -94° 36' 34.92" W (45.1702, -93.3903) coordinates. The local time in Champlin is 02:11 (13.03.2025)
Sannicolau Mare is located in Timiş, Romania within 46° 3' 48.96" N 20° 36' 45" E (46.0636, 20.6125) coordinates. The local time in Sannicolau Mare is 10:11 (13.03.2025)
The calculated flying distance from Sannicolau Mare to Sannicolau Mare is 4,963.47 miles which is equal to 7,987.93 km.
Champlin, Minnesota, United States
Related Distances from Champlin
Sannicolau Mare, Timiş, Romania