Distance from Champlin to Sassenberg
The shortest distance (air line) between Champlin and Sassenberg is 4,269.12 mi (6,870.48 km).
How far is Champlin from Sassenberg
Champlin is located in Minnesota, United States within 45° 10' 12.72" N -94° 36' 34.92" W (45.1702, -93.3903) coordinates. The local time in Champlin is 20:22 (24.02.2025)
Sassenberg is located in Warendorf, Germany within 51° 59' 22.92" N 8° 2' 26.88" E (51.9897, 8.0408) coordinates. The local time in Sassenberg is 03:22 (25.02.2025)
The calculated flying distance from Sassenberg to Sassenberg is 4,269.12 miles which is equal to 6,870.48 km.
Champlin, Minnesota, United States
Related Distances from Champlin
Sassenberg, Warendorf, Germany