Distance from Champlin to Sendenhorst
The shortest distance (air line) between Champlin and Sendenhorst is 4,268.24 mi (6,869.08 km).
How far is Champlin from Sendenhorst
Champlin is located in Minnesota, United States within 45° 10' 12.72" N -94° 36' 34.92" W (45.1702, -93.3903) coordinates. The local time in Champlin is 00:30 (25.02.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 07:30 (25.02.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 4,268.24 miles which is equal to 6,869.08 km.
Champlin, Minnesota, United States
Related Distances from Champlin
Sendenhorst, Warendorf, Germany