Distance from Charlottesville to Diepenbeek
The shortest distance (air line) between Charlottesville and Diepenbeek is 4,002.45 mi (6,441.33 km).
How far is Charlottesville from Diepenbeek
Charlottesville is located in Virginia, United States within 38° 2' 15" N -79° 30' 52.2" W (38.0375, -78.4855) coordinates. The local time in Charlottesville is 22:47 (31.01.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 04:47 (01.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,002.45 miles which is equal to 6,441.33 km.
Charlottesville, Virginia, United States
Related Distances from Charlottesville
Diepenbeek, Arr. Hasselt, Belgium