Distance from Chateaubriant to Mercato San Severino
The shortest distance (air line) between Chateaubriant and Mercato San Severino is 928.84 mi (1,494.82 km).
How far is Chateaubriant from Mercato San Severino
Chateaubriant is located in Loire-Atlantique, France within 47° 43' 0.84" N -2° 37' 26.04" W (47.7169, -1.3761) coordinates. The local time in Chateaubriant is 17:06 (29.05.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 17:06 (29.05.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 928.84 miles which is equal to 1,494.82 km.
Chateaubriant, Loire-Atlantique, France
Related Distances from Chateaubriant
Mercato San Severino, Salerno, Italy