Distance from Chateaubriant to Montceau-les-Mines
The shortest distance (air line) between Chateaubriant and Montceau-les-Mines is 279.25 mi (449.41 km).
How far is Chateaubriant from Montceau-les-Mines
Chateaubriant is located in Loire-Atlantique, France within 47° 43' 0.84" N -2° 37' 26.04" W (47.7169, -1.3761) coordinates. The local time in Chateaubriant is 06:30 (29.04.2025)
Montceau-les-Mines is located in Saône-et-Loire, France within 46° 40' 0.84" N 4° 22' 8.04" E (46.6669, 4.3689) coordinates. The local time in Montceau-les-Mines is 06:30 (29.04.2025)
The calculated flying distance from Montceau-les-Mines to Montceau-les-Mines is 279.25 miles which is equal to 449.41 km.
Chateaubriant, Loire-Atlantique, France
Related Distances from Chateaubriant
Montceau-les-Mines, Saône-et-Loire, France