Distance from Chateaubriant to San Severino Marche
The shortest distance (air line) between Chateaubriant and San Severino Marche is 768.73 mi (1,237.16 km).
How far is Chateaubriant from San Severino Marche
Chateaubriant is located in Loire-Atlantique, France within 47° 43' 0.84" N -2° 37' 26.04" W (47.7169, -1.3761) coordinates. The local time in Chateaubriant is 04:34 (21.05.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 04:34 (21.05.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 768.73 miles which is equal to 1,237.16 km.
Chateaubriant, Loire-Atlantique, France
Related Distances from Chateaubriant
San Severino Marche, Macerata, Italy