Distance from Chateauneuf-les-Martigues to Bad Sassendorf
The shortest distance (air line) between Chateauneuf-les-Martigues and Bad Sassendorf is 583.52 mi (939.08 km).
How far is Chateauneuf-les-Martigues from Bad Sassendorf
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 18:41 (07.05.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 18:41 (07.05.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 583.52 miles which is equal to 939.08 km.
Chateauneuf-les-Martigues, Bouches-du-Rhône, France
Related Distances from Chateauneuf-les-Martigues
Bad Sassendorf, Soest, Germany