Distance from Chateauneuf-les-Martigues to Ceres
The shortest distance (air line) between Chateauneuf-les-Martigues and Ceres is 5,903.18 mi (9,500.24 km).
How far is Chateauneuf-les-Martigues from Ceres
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 01:37 (11.12.2025)
Ceres is located in California, United States within 37° 35' 42.72" N -121° 2' 16.8" W (37.5952, -120.9620) coordinates. The local time in Ceres is 16:37 (10.12.2025)
The calculated flying distance from Ceres to Ceres is 5,903.18 miles which is equal to 9,500.24 km.
Chateauneuf-les-Martigues, Bouches-du-Rhône, France
Related Distances from Chateauneuf-les-Martigues
Ceres, California, United States