Distance from Chateauneuf-les-Martigues to Cesky Tesin
The shortest distance (air line) between Chateauneuf-les-Martigues and Cesky Tesin is 774.22 mi (1,245.99 km).
How far is Chateauneuf-les-Martigues from Cesky Tesin
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 11:53 (03.12.2024)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 11:53 (03.12.2024)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 774.22 miles which is equal to 1,245.99 km.
Chateauneuf-les-Martigues, Bouches-du-Rhône, France
Related Distances from Chateauneuf-les-Martigues
Cesky Tesin, Moravskoslezský kraj, Czechia