Distance from Chateauneuf-les-Martigues to Sint-Andries
The shortest distance (air line) between Chateauneuf-les-Martigues and Sint-Andries is 547.96 mi (881.86 km).
How far is Chateauneuf-les-Martigues from Sint-Andries
Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 23:40 (01.12.2024)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 23:40 (01.12.2024)
The calculated flying distance from Sint-Andries to Sint-Andries is 547.96 miles which is equal to 881.86 km.
Chateauneuf-les-Martigues, Bouches-du-Rhône, France
Related Distances from Chateauneuf-les-Martigues
Sint-Andries, Arr. Brugge, Belgium