Distance from Cheat Lake to Aleksandrovac
The shortest distance (air line) between Cheat Lake and Aleksandrovac is 4,873.23 mi (7,842.71 km).
How far is Cheat Lake from Aleksandrovac
Cheat Lake is located in West Virginia, United States within 39° 40' 1.2" N -80° 8' 36.96" W (39.6670, -79.8564) coordinates. The local time in Cheat Lake is 19:06 (24.05.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 01:06 (25.05.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 4,873.23 miles which is equal to 7,842.71 km.
Cheat Lake, West Virginia, United States
Related Distances from Cheat Lake
Aleksandrovac, Rasinska oblast, Serbia