Distance from Chestnut Ridge to Celakovice
The shortest distance (air line) between Chestnut Ridge and Celakovice is 4,078.26 mi (6,563.32 km).
How far is Chestnut Ridge from Celakovice
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 12:02 (24.11.2024)
Celakovice is located in Středočeský kraj, Czechia within 50° 9' 38.16" N 14° 45' 0" E (50.1606, 14.7500) coordinates. The local time in Celakovice is 18:02 (24.11.2024)
The calculated flying distance from Celakovice to Celakovice is 4,078.26 miles which is equal to 6,563.32 km.
Chestnut Ridge, New York, United States
Related Distances from Chestnut Ridge
Celakovice, Středočeský kraj, Czechia