Distance from Chestnut Ridge to Dimitrovgrad
The shortest distance (air line) between Chestnut Ridge and Dimitrovgrad is 4,663.75 mi (7,505.58 km).
How far is Chestnut Ridge from Dimitrovgrad
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 04:28 (24.11.2024)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 10:28 (24.11.2024)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 4,663.75 miles which is equal to 7,505.58 km.
Chestnut Ridge, New York, United States
Related Distances from Chestnut Ridge
Dimitrovgrad, Pirotska oblast, Serbia