Distance from Chestnut Ridge to Drawsko Pomorskie
The shortest distance (air line) between Chestnut Ridge and Drawsko Pomorskie is 4,008.83 mi (6,451.59 km).
How far is Chestnut Ridge from Drawsko Pomorskie
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 15:41 (02.01.2026)
Drawsko Pomorskie is located in Szczecinecko-pyrzycki, Poland within 53° 31' 59.88" N 15° 48' 0" E (53.5333, 15.8000) coordinates. The local time in Drawsko Pomorskie is 21:41 (02.01.2026)
The calculated flying distance from Drawsko Pomorskie to Drawsko Pomorskie is 4,008.83 miles which is equal to 6,451.59 km.
Chestnut Ridge, New York, United States
Related Distances from Chestnut Ridge
Drawsko Pomorskie, Szczecinecko-pyrzycki, Poland