Distance from Chestnut Ridge to Janow Lubelski
The shortest distance (air line) between Chestnut Ridge and Janow Lubelski is 4,349.02 mi (6,999.07 km).
How far is Chestnut Ridge from Janow Lubelski
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 12:52 (02.01.2026)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 18:52 (02.01.2026)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 4,349.02 miles which is equal to 6,999.07 km.
Chestnut Ridge, New York, United States
Related Distances from Chestnut Ridge
Janow Lubelski, Puławski, Poland