Distance from Chestnut Ridge to Sajoszentpeter
The shortest distance (air line) between Chestnut Ridge and Sajoszentpeter is 4,378.45 mi (7,046.44 km).
How far is Chestnut Ridge from Sajoszentpeter
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 20:06 (17.05.2025)
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 02:06 (18.05.2025)
The calculated flying distance from Sajoszentpeter to Sajoszentpeter is 4,378.45 miles which is equal to 7,046.44 km.
Chestnut Ridge, New York, United States
Related Distances from Chestnut Ridge
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary