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      Distance from Chestnut Ridge to San Pancrazio Salentino

      The shortest distance (air line) between Chestnut Ridge and San Pancrazio Salentino is 4,558.38 mi (7,336.00 km).

      How far is Chestnut Ridge from San Pancrazio Salentino

      Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 00:08 (25.05.2025)

      San Pancrazio Salentino is located in Brindisi, Italy within 40° 25' 0.12" N 17° 49' 59.88" E (40.4167, 17.8333) coordinates. The local time in San Pancrazio Salentino is 06:08 (25.05.2025)

      The calculated flying distance from San Pancrazio Salentino to San Pancrazio Salentino is 4,558.38 miles which is equal to 7,336.00 km.

      Chestnut Ridge, New York, United States

      Related Distances from Chestnut Ridge

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      Chestnut Ridge to Portland (Oregon)2,424.84 mi (3,902.40 km)
      Chestnut Ridge to Los Angeles (California)2,448.17 mi (3,939.95 km)
      Chestnut Ridge to San Francisco (California)2,559.89 mi (4,119.74 km)
      Chestnut Ridge to Queens (New York)26.65 mi (42.90 km)
      Chestnut Ridge to New York (New York)27.70 mi (44.57 km)
      Chestnut Ridge to Brooklyn (New York)30.41 mi (48.94 km)
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      San Pancrazio Salentino, Brindisi, Italy

      Related Distances to San Pancrazio Salentino