Distance from Chestnut Ridge to San Severino Marche
The shortest distance (air line) between Chestnut Ridge and San Severino Marche is 4,251.70 mi (6,842.45 km).
How far is Chestnut Ridge from San Severino Marche
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 19:01 (27.05.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 01:01 (28.05.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 4,251.70 miles which is equal to 6,842.45 km.
Chestnut Ridge, New York, United States
Related Distances from Chestnut Ridge
San Severino Marche, Macerata, Italy