Distance from Chestnut Ridge to Sokolow Podlaski
The shortest distance (air line) between Chestnut Ridge and Sokolow Podlaski is 4,280.76 mi (6,889.22 km).
How far is Chestnut Ridge from Sokolow Podlaski
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 22:47 (06.01.2026)
Sokolow Podlaski is located in Siedlecki, Poland within 52° 23' 60" N 22° 15' 0" E (52.4000, 22.2500) coordinates. The local time in Sokolow Podlaski is 04:47 (07.01.2026)
The calculated flying distance from Sokolow Podlaski to Sokolow Podlaski is 4,280.76 miles which is equal to 6,889.22 km.
Chestnut Ridge, New York, United States
Related Distances from Chestnut Ridge
Sokolow Podlaski, Siedlecki, Poland