Distance from Chestnut Ridge to Stamboliyski
The shortest distance (air line) between Chestnut Ridge and Stamboliyski is 4,771.63 mi (7,679.19 km).
How far is Chestnut Ridge from Stamboliyski
Chestnut Ridge is located in New York, United States within 41° 4' 58.44" N -75° 56' 41.64" W (41.0829, -74.0551) coordinates. The local time in Chestnut Ridge is 06:43 (24.11.2024)
Stamboliyski is located in Plovdiv, Bulgaria within 42° 7' 59.88" N 24° 31' 59.88" E (42.1333, 24.5333) coordinates. The local time in Stamboliyski is 13:43 (24.11.2024)
The calculated flying distance from Stamboliyski to Stamboliyski is 4,771.63 miles which is equal to 7,679.19 km.
Chestnut Ridge, New York, United States
Related Distances from Chestnut Ridge
Stamboliyski, Plovdiv, Bulgaria