Distance from Choctaw to Sveti Ivan Zelina
The shortest distance (air line) between Choctaw and Sveti Ivan Zelina is 5,455.90 mi (8,780.42 km).
How far is Choctaw from Sveti Ivan Zelina
Choctaw is located in Oklahoma, United States within 35° 28' 48.72" N -98° 44' 0.24" W (35.4802, -97.2666) coordinates. The local time in Choctaw is 07:23 (05.06.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 14:23 (05.06.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,455.90 miles which is equal to 8,780.42 km.
Choctaw, Oklahoma, United States
Related Distances from Choctaw
Sveti Ivan Zelina, Zagrebačka županija, Croatia