Distance from Christiansburg to Bad Segeberg
The shortest distance (air line) between Christiansburg and Bad Segeberg is 4,227.20 mi (6,803.02 km).
How far is Christiansburg from Bad Segeberg
Christiansburg is located in Virginia, United States within 37° 8' 26.16" N -81° 35' 47.04" W (37.1406, -80.4036) coordinates. The local time in Christiansburg is 17:43 (18.11.2024)
Bad Segeberg is located in Segeberg, Germany within 53° 55' 0.12" N 10° 19' 0.12" E (53.9167, 10.3167) coordinates. The local time in Bad Segeberg is 23:43 (18.11.2024)
The calculated flying distance from Bad Segeberg to Bad Segeberg is 4,227.20 miles which is equal to 6,803.02 km.
Christiansburg, Virginia, United States
Related Distances from Christiansburg
Bad Segeberg, Segeberg, Germany