Distance from Christiansburg to Kaltenkirchen
The shortest distance (air line) between Christiansburg and Kaltenkirchen is 4,216.18 mi (6,785.29 km).
How far is Christiansburg from Kaltenkirchen
Christiansburg is located in Virginia, United States within 37° 8' 26.16" N -81° 35' 47.04" W (37.1406, -80.4036) coordinates. The local time in Christiansburg is 15:22 (19.11.2024)
Kaltenkirchen is located in Segeberg, Germany within 53° 50' 22.92" N 9° 57' 37.08" E (53.8397, 9.9603) coordinates. The local time in Kaltenkirchen is 21:22 (19.11.2024)
The calculated flying distance from Kaltenkirchen to Kaltenkirchen is 4,216.18 miles which is equal to 6,785.29 km.
Christiansburg, Virginia, United States
Related Distances from Christiansburg
Kaltenkirchen, Segeberg, Germany