Distance from Christiansburg to Opglabbeek
The shortest distance (air line) between Christiansburg and Opglabbeek is 4,124.44 mi (6,637.64 km).
How far is Christiansburg from Opglabbeek
Christiansburg is located in Virginia, United States within 37° 8' 26.16" N -81° 35' 47.04" W (37.1406, -80.4036) coordinates. The local time in Christiansburg is 10:05 (15.11.2024)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 16:05 (15.11.2024)
The calculated flying distance from Opglabbeek to Opglabbeek is 4,124.44 miles which is equal to 6,637.64 km.
Christiansburg, Virginia, United States
Related Distances from Christiansburg
Opglabbeek, Arr. Maaseik, Belgium