Distance from Christiansburg to Sint-Katelijne-Waver
The shortest distance (air line) between Christiansburg and Sint-Katelijne-Waver is 4,081.89 mi (6,569.17 km).
How far is Christiansburg from Sint-Katelijne-Waver
Christiansburg is located in Virginia, United States within 37° 8' 26.16" N -81° 35' 47.04" W (37.1406, -80.4036) coordinates. The local time in Christiansburg is 11:01 (15.11.2024)
Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 17:01 (15.11.2024)
The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 4,081.89 miles which is equal to 6,569.17 km.
Christiansburg, Virginia, United States
Related Distances from Christiansburg
Sint-Katelijne-Waver, Arr. Mechelen, Belgium