Distance from Citrus Heights to San Giuseppe Vesuviano
The shortest distance (air line) between Citrus Heights and San Giuseppe Vesuviano is 6,275.78 mi (10,099.89 km).
How far is Citrus Heights from San Giuseppe Vesuviano
Citrus Heights is located in California, United States within 38° 41' 41.28" N -122° 42' 43.2" W (38.6948, -121.2880) coordinates. The local time in Citrus Heights is 17:23 (01.06.2025)
San Giuseppe Vesuviano is located in Napoli, Italy within 40° 49' 59.88" N 14° 30' 0" E (40.8333, 14.5000) coordinates. The local time in San Giuseppe Vesuviano is 02:23 (02.06.2025)
The calculated flying distance from San Giuseppe Vesuviano to San Giuseppe Vesuviano is 6,275.78 miles which is equal to 10,099.89 km.
Citrus Heights, California, United States
Related Distances from Citrus Heights
San Giuseppe Vesuviano, Napoli, Italy