Distance from Civita Castellana to San Giuseppe Vesuviano
The shortest distance (air line) between Civita Castellana and San Giuseppe Vesuviano is 147.94 mi (238.09 km).
How far is Civita Castellana from San Giuseppe Vesuviano
Civita Castellana is located in Viterbo, Italy within 42° 17' 45.96" N 12° 24' 36" E (42.2961, 12.4100) coordinates. The local time in Civita Castellana is 11:21 (24.02.2025)
San Giuseppe Vesuviano is located in Napoli, Italy within 40° 49' 59.88" N 14° 30' 0" E (40.8333, 14.5000) coordinates. The local time in San Giuseppe Vesuviano is 11:21 (24.02.2025)
The calculated flying distance from San Giuseppe Vesuviano to San Giuseppe Vesuviano is 147.94 miles which is equal to 238.09 km.
Civita Castellana, Viterbo, Italy
Related Distances from Civita Castellana
San Giuseppe Vesuviano, Napoli, Italy