Distance from Civitavecchia to Alexandroupoli
The shortest distance (air line) between Civitavecchia and Alexandroupoli is 732.46 mi (1,178.78 km).
How far is Civitavecchia from Alexandroupoli
Civitavecchia is located in Roma, Italy within 42° 6' 0" N 11° 48' 0" E (42.1000, 11.8000) coordinates. The local time in Civitavecchia is 04:17 (08.02.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 05:17 (08.02.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 732.46 miles which is equal to 1,178.78 km.