Distance from Clarksburg to Aleksandrow Lodzki
The shortest distance (air line) between Clarksburg and Aleksandrow Lodzki is 4,404.69 mi (7,088.66 km).
How far is Clarksburg from Aleksandrow Lodzki
Clarksburg is located in Maryland, United States within 39° 13' 28.56" N -78° 44' 2.76" W (39.2246, -77.2659) coordinates. The local time in Clarksburg is 12:28 (25.02.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 18:28 (25.02.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,404.69 miles which is equal to 7,088.66 km.
Clarksburg, Maryland, United States
Related Distances from Clarksburg
Aleksandrow Lodzki, Łódzki, Poland