Distance from Clarksburg to Fontainebleau
The shortest distance (air line) between Clarksburg and Fontainebleau is 3,853.28 mi (6,201.26 km).
How far is Clarksburg from Fontainebleau
Clarksburg is located in Maryland, United States within 39° 13' 28.56" N -78° 44' 2.76" W (39.2246, -77.2659) coordinates. The local time in Clarksburg is 19:00 (02.02.2025)
Fontainebleau is located in Seine-et-Marne, France within 48° 24' 32.04" N 2° 42' 6.12" E (48.4089, 2.7017) coordinates. The local time in Fontainebleau is 01:00 (03.02.2025)
The calculated flying distance from Fontainebleau to Fontainebleau is 3,853.28 miles which is equal to 6,201.26 km.
Clarksburg, Maryland, United States
Related Distances from Clarksburg
Fontainebleau, Seine-et-Marne, France