Distance from Clarksburg to Mercato San Severino
The shortest distance (air line) between Clarksburg and Mercato San Severino is 4,622.70 mi (7,439.51 km).
How far is Clarksburg from Mercato San Severino
Clarksburg is located in Maryland, United States within 39° 13' 28.56" N -78° 44' 2.76" W (39.2246, -77.2659) coordinates. The local time in Clarksburg is 05:51 (12.02.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 11:51 (12.02.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 4,622.70 miles which is equal to 7,439.51 km.
Clarksburg, Maryland, United States
Related Distances from Clarksburg
Mercato San Severino, Salerno, Italy