Distance from Clarksburg to San Giorgio di Piano
The shortest distance (air line) between Clarksburg and San Giorgio di Piano is 4,337.72 mi (6,980.88 km).
How far is Clarksburg from San Giorgio di Piano
Clarksburg is located in Maryland, United States within 39° 13' 28.56" N -78° 44' 2.76" W (39.2246, -77.2659) coordinates. The local time in Clarksburg is 20:27 (20.02.2025)
San Giorgio di Piano is located in Bologna, Italy within 44° 38' 60" N 11° 22' 59.88" E (44.6500, 11.3833) coordinates. The local time in San Giorgio di Piano is 02:27 (21.02.2025)
The calculated flying distance from San Giorgio di Piano to San Giorgio di Piano is 4,337.72 miles which is equal to 6,980.88 km.
Clarksburg, Maryland, United States
Related Distances from Clarksburg
San Giorgio di Piano, Bologna, Italy