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      Distance from Clarksburg to San Gregorio di Catania

      The shortest distance (air line) between Clarksburg and San Gregorio di Catania is 4,760.45 mi (7,661.21 km).

      How far is Clarksburg from San Gregorio di Catania

      Clarksburg is located in Maryland, United States within 39° 13' 28.56" N -78° 44' 2.76" W (39.2246, -77.2659) coordinates. The local time in Clarksburg is 20:54 (20.02.2025)

      San Gregorio di Catania is located in Catania, Italy within 37° 34' 0.12" N 15° 7' 0.12" E (37.5667, 15.1167) coordinates. The local time in San Gregorio di Catania is 02:54 (21.02.2025)

      The calculated flying distance from San Gregorio di Catania to San Gregorio di Catania is 4,760.45 miles which is equal to 7,661.21 km.

      Clarksburg, Maryland, United States

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      San Gregorio di Catania, Catania, Italy

      Related Distances to San Gregorio di Catania