Distance from Clarksburg to San Lazzaro di Savena
The shortest distance (air line) between Clarksburg and San Lazzaro di Savena is 4,344.71 mi (6,992.13 km).
How far is Clarksburg from San Lazzaro di Savena
Clarksburg is located in Maryland, United States within 39° 13' 28.56" N -78° 44' 2.76" W (39.2246, -77.2659) coordinates. The local time in Clarksburg is 21:02 (20.02.2025)
San Lazzaro di Savena is located in Bologna, Italy within 44° 28' 17.76" N 11° 24' 17.64" E (44.4716, 11.4049) coordinates. The local time in San Lazzaro di Savena is 03:02 (21.02.2025)
The calculated flying distance from San Lazzaro di Savena to San Lazzaro di Savena is 4,344.71 miles which is equal to 6,992.13 km.
Clarksburg, Maryland, United States
Related Distances from Clarksburg
San Lazzaro di Savena, Bologna, Italy