Distance from Clarksburg to San Severino Marche
The shortest distance (air line) between Clarksburg and San Severino Marche is 4,464.24 mi (7,184.50 km).
How far is Clarksburg from San Severino Marche
Clarksburg is located in Maryland, United States within 39° 13' 28.56" N -78° 44' 2.76" W (39.2246, -77.2659) coordinates. The local time in Clarksburg is 20:49 (20.02.2025)
San Severino Marche is located in Macerata, Italy within 43° 13' 44.04" N 13° 10' 37.56" E (43.2289, 13.1771) coordinates. The local time in San Severino Marche is 02:49 (21.02.2025)
The calculated flying distance from San Severino Marche to San Severino Marche is 4,464.24 miles which is equal to 7,184.50 km.
Clarksburg, Maryland, United States
Related Distances from Clarksburg
San Severino Marche, Macerata, Italy