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      Distance from Clarksburg to San Vicente de Baracaldo

      The shortest distance (air line) between Clarksburg and San Vicente de Baracaldo is 3,737.45 mi (6,014.84 km).

      How far is Clarksburg from San Vicente de Baracaldo

      Clarksburg is located in Maryland, United States within 39° 13' 28.56" N -78° 44' 2.76" W (39.2246, -77.2659) coordinates. The local time in Clarksburg is 09:41 (04.03.2025)

      San Vicente de Baracaldo is located in Bizkaia, Spain within 43° 17' 49.92" N -3° 0' 29.88" W (43.2972, -2.9917) coordinates. The local time in San Vicente de Baracaldo is 15:41 (04.03.2025)

      The calculated flying distance from San Vicente de Baracaldo to San Vicente de Baracaldo is 3,737.45 miles which is equal to 6,014.84 km.

      Clarksburg, Maryland, United States

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      San Vicente de Baracaldo, Bizkaia, Spain

      Related Distances to San Vicente de Baracaldo